**913 10.9689**1 hours ago Analytical Proofs of **non** differentiability. Example 1: Show analytically that **function** f defined below is **non differentiable** at x = 0. f (x) = \begin {cases} x^2 & x \textgreater 0 \\ - x & x \textless 0 \\ 0 & x = 0 \end {cases} Solution to Example 1. One way to answer the above question, is to calculate the derivative at x = 0.

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6 hours ago Here is an approach that **you** can use for numerical functions that at least have a left and right derivative. If such a **function** isn't **differentiable** in a **point** that is equivalent to the left and right derivatives being unequal, so look at the left and right finite difference approximation of the derivative, and see where they disagree.

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3 hours ago ðŸ‘‰ Learn how to determine the differentiability of a **function**. A **function** is said to be **differentiable** if the derivative exists at each **point** in its domain.

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4 hours ago Recall that for the "Differentiability theorem" if all the partial derivatives exist and are continuous in a neighborhood of a **point** then (i.e. sufficient condition) the **function** is **differentiable** at that **point**.

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3 hours ago **To** ask any doubt in Math download Doubtnut: https://goo.gl/s0kUoeQuestion: If f(x)=[sin x]+[cos x],** x in** [0,2pi], where [.] denotes the greatest integer func

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3 hours ago To ask any doubt in Math download Doubtnut: https://goo.gl/s0kUoeQuestion: Let f(x) = [** n** + p sin x], x in (0,pi),** n in** Z,** p** a prime number and [x] = the gr

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8 hours ago Here we are going to see how to prove that **the function** is not **differentiable** at the given **point**. The **function** is **differentiable** from the left and right. As in the case of the existence of limits of a **function** at x 0, it follows that. exists if and only if both. exist and f' (x 0 -) = f' (x 0 +) Hence. if and only if f' (x 0 -) = f' (x 0 +).

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3 hours ago ðŸ‘‰ Learn how to determine the differentiability of a **function**. A **function** is said to be **differentiable** if the derivative exists at each **point** in its domain.

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1 hours ago Here we are going to see how to check differentiability of a **function** at a **point**. The **function** is **differentiable** from the left and right. As in the case of the existence of limits of a **function** at x 0, it follows that. if and only if f' (x 0 -) = f' (x 0 +) . If any one of the condition fails then f' (x) is not **differentiable** at x 0.

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8 hours ago Answer (1 of 4): Case 1 : Firstly check the continuity of that **function**. The **function** is not **differentiable** at any **point** if the **function** is discontinuous at that **point**.. Because the curve doesn't exist at the **point** of discontinuity, so not **differentiable** at that **point**. Case 2 : â€¦

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Just Now **Points** of **Non**-Differentiability. Let us show that in the limit the derivative of the **function** essentially reproduces the derivative of the original **function** .Stating it more precisely, we will show that, if the **function** is continuous but has an isolated **point** of **non**-differentiability at , then in the limit the derivative of tends to the average of the two lateral limits of the derivative of to

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Just Now Answer (1 of 5): Not necessarily. It depends on how many **points** of **non**-differentiability there are. Take a Weierstrass **function** (far-fetched example): [math]\begin

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5 hours ago Homework Statement **Find** the **points** at which the **function** is not **differentiable**. Homework Equations It is not asked to check differentiability at a particular **point**. How **do** I **find** the **points** which are not **differentiable**? The **function** is not continuous at x=0

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3 hours ago Breaking **points** are such **points** where there is not possible to draw a tangent to the curve at that **point** .For an example y = x is a **function** which is continuos at (0,0) but not **differentiable**. For the **function** y = x , (0,0) is a breaking **point**.**. And if **you find** the left hand limit, L f ` (P) and right hand limit, R f ` (P) of a **function** f

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Just Now A parabola is **differentiable** at its vertex because, while it has negative slope to the left and positive slope to the right, the slope from both directions shrinks to 0 as **you** approach the vertex. But in, say, the absolute value **function**, the slopes are -1 to the left and 1 to the right, constantly.

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7 hours ago View solution. >. The number of **points** of **non**-differentiability of h ( x) = âˆ£ f ( g ( x)) âˆ£ is. Hard. View solution. >. Let f: R â†’ R be a **differentiable function** satisfying f ( 3 x + y ) = 3 2 + f ( x) + f ( y) âˆ€ x, y âˆˆ R and f â€² ( 2) = 2, then answer the following questions: The â€¦

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5 hours ago Example: The **function** g(x) = x with Domain (0, +âˆž) The domain is from but not including 0 onwards (all positive values).. Which IS **differentiable**. And I am "absolutely positive" about that :) So the **function** g(x) = x with Domain (0, +âˆž) is **differentiable**.. We could also restrict the domain in other ways to avoid x=0 (such as all negative Real Numbers, all **non**-zero Real â€¦

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